A canonical structure will be more stable if
(a) it has more number of `pi` bonds than if it has less number of `pi` bonds.
(b) the octate of all atoms are complete than if octate of all atoms are not complete.
(c ) it involves cyclic delocalization of `(4n + 2) pi -` electrons than if it involves acyclic delocalization of `(4n + 2) pi -`electrons.
(d) it involves cyclic delocalization `(4n) pi `- electrons than if it involves acyclic delocalizationof `(4 n) pi -` electrons.
(e ) `+ ve` charge is on more electronegative atom than if `+ve` charge is on less electronegative atoms.
(f) `-ve` charge is on more electronegative atom than if`–ve` charge is on less electronegative atom.

Answer

To determine the stability of a canonical structure, we can analyze each of the given statements based on the principles of resonance, octet rule, and aromaticity. Let's evaluate each option step by step:

### Step-by-Step Solution:

1. **Option (a)**: A canonical structure will be more stable if it has more number of π bonds than if it has less number of π bonds.
- **Analysis**: More π bonds generally indicate greater resonance stabilization. Therefore, this statement is **true**.

2. **Option (b)**: A canonical structure will be more stable if the octet of all atoms are complete than if the octet of all atoms are not complete.
- **Analysis**: According to the octet rule, atoms are more stable when they have a complete octet. Thus, this statement is **true**.

3. **Option (c)**: A canonical structure will be more stable if it involves cyclic delocalization of (4n + 2) π electrons than if it involves acyclic delocalization of (4n + 2) π electrons.
- **Analysis**: According to Huckel's rule, cyclic delocalization of (4n + 2) π electrons leads to aromatic stability, which is more stable than acyclic systems. Hence, this statement is **true**.

4. **Option (d)**: A canonical structure will be more stable if it involves cyclic delocalization of (4n) π electrons than if it involves acyclic delocalization of (4n) π electrons.
- **Analysis**: Structures with (4n) π electrons are considered anti-aromatic, which are less stable compared to acyclic systems. Therefore, this statement is **false**.

5. **Option (e)**: A canonical structure will be more stable if the +ve charge is on more electronegative atom than if +ve charge is on less electronegative atoms.
- **Analysis**: A positive charge is less stable on electronegative atoms because they are more likely to attract electrons. Therefore, this statement is **false**.

6. **Option (f)**: A canonical structure will be more stable if -ve charge is on more electronegative atom than if -ve charge is on less electronegative atom.
- **Analysis**: A negative charge is more stable on electronegative atoms, as they can better accommodate the extra electron density. Thus, this statement is **true**.

### Summary of Correct Options:
The correct options that indicate a more stable canonical structure are: **(a), (b), (c), and (f)**.