Write stability order of following intermediates:
`(a)CH_(3) - overset(o+)CH_(2)" "(b)CH_(3) - overset(o+)CH - CH_(3)`
`(c)CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)C o+`

Answer

To determine the stability order of the given intermediates, we need to analyze the structure and the type of carbocations involved. Let's break down the intermediates one by one.

### Step 1: Identify the Structures
1. **Intermediate (a)**: CH₃ - C⁺H₂
- This is a primary carbocation since the positively charged carbon is attached to only one carbon (the methyl group).

2. **Intermediate (b)**: CH₃ - C⁺H - CH₃
- This is a secondary carbocation because the positively charged carbon is attached to two other carbons (one methyl and one hydrogen).

3. **Intermediate (c)**: CH₃ - C(CH₃)₂⁺
- This is a tertiary carbocation since the positively charged carbon is attached to three other carbons (three methyl groups).

### Step 2: Analyze Stability Factors
- Carbocations are stabilized by the inductive effect and hyperconjugation.
- Tertiary carbocations are the most stable due to the presence of three alkyl groups that can donate electron density to the positively charged carbon.
- Secondary carbocations are less stable than tertiary but more stable than primary due to the presence of two alkyl groups.
- Primary carbocations are the least stable because they have only one alkyl group to stabilize the positive charge.

### Step 3: Order the Stability
Based on the analysis:
- **Intermediate (c)** is tertiary and the most stable.
- **Intermediate (b)** is secondary and more stable than primary.
- **Intermediate (a)** is primary and the least stable.

Thus, the stability order is:
**C > B > A**

### Final Answer
The stability order of the intermediates is:
**C > B > A**