Write stability order of following intermediates:
`(a)overset(Ө)CH_(2) - underset(O)underset(||)CH" "(b) overset(Theta)(CH)_(2) - CH_(3)`

Answer

To determine the stability order of the given intermediates, we need to analyze each structure based on the factors affecting their stability, such as resonance and inductive effects.

### Step-by-Step Solution:

1. **Identify the Structures:**
- (a) The first intermediate is represented as `CH2 - C(=O) - H` with a negative charge on the carbon adjacent to the carbonyl group.
- (b) The second intermediate is represented as `CH2^- - CH3`.

2. **Analyze Intermediate (a):**
- The structure `CH2 - C(=O) - H` has a carbonyl group (C=O) which can stabilize the negative charge through resonance.
- The negative charge on the carbon can delocalize into the carbonyl group, leading to resonance structures that distribute the charge over multiple atoms.
- This resonance stabilization increases the overall stability of this intermediate.

3. **Analyze Intermediate (b):**
- The structure `CH2^- - CH3` has a negative charge on the carbon adjacent to a methyl group (CH3).
- The methyl group exhibits a +I (positive inductive) effect, which means it pushes electron density towards the negatively charged carbon.
- This increase in charge density makes the negative charge less stable because it is less able to disperse.

4. **Compare Stability:**
- Intermediate (a) benefits from resonance stabilization, making it more stable.
- Intermediate (b) is destabilized by the +I effect from the methyl group, making it less stable.

5. **Write the Stability Order:**
- Based on the analysis, we can conclude that the stability order of the intermediates is:
\[ \text{(a) > (b)} \]

### Final Answer:
The stability order of the intermediates is:
\[ \text{(a) > (b)} \]