A parallel plate capacitor has plates of area `4 m^2` separated by distance of 0.5 mm. The capacitor is connected across a cell of emf 100 V.
A dielectric slab of thickness 0.5 mm is inserted inside this capacitor after it has been disconnected from the cell. Find the answers to part (a) if K = 3.

Explanation

To solve the problem step by step, we will calculate the capacitance of the parallel plate capacitor, the charge stored, and the energy stored before and after the dielectric slab is inserted.

### Step 1: Calculate the Capacitance (C) of the Capacitor

The formula for the capacitance of a parallel plate capacitor is given by:

\[
C = \frac{A \cdot \epsilon_0}{d}
...