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A hiker stands on the edge of a cliff 49...

A hiker stands on the edge of a cliff `490 m` above the ground and throwns a stone horiozontally with an initial speed of `15ms^(-1)` neglecting air resistance.The time taken by the stone to reach the ground in seconds is `(g=9.8ms^(2))`

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time = 10 seconds
`V=sqrt(V_(x)^(2)+V_(y)^(2))=sqrt(15^(2)-98^(2))=99.1m//s^(-1)`.
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