What happens when `SO_(2)` is passed in acidified `KMnO_(4)` solution ?

Explanation

To determine what happens when \( SO_2 \) is passed through acidified \( KMnO_4 \) solution, we can follow these steps:

### Step 1: Understand the Reactants
- \( KMnO_4 \) (Potassium permanganate) is a strong oxidizing agent, especially in acidic medium.
- \( SO_2 \) (Sulfur dioxide) can act as a reducing agent.

### Step 2: Identify the Reaction Conditions
- The reaction occurs in an acidic medium, which means we need to consider the presence of \( H^+ \) ions from the acid (usually sulfuric acid, \( H_2SO_4 \)).
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