Write a chemical equation to represent the oxidizing nature of `XeF_(4)`.

Explanation

To represent the oxidizing nature of \( \text{XeF}_4 \), we can write a chemical equation that demonstrates its ability to act as an oxidizing agent. Here’s a step-by-step solution:

### Step 1: Determine the oxidation state of xenon in \( \text{XeF}_4 \)
In \( \text{XeF}_4 \), fluorine (F) has an oxidation state of -1. Since there are four fluorine atoms, their total contribution to the oxidation state is -4. Let the oxidation state of xenon (Xe) be \( x \).

The equation for the oxidation state is:
\[
x + 4(-1) = 0
...