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XeF(4) +SbF(5) to...

`XeF_(4) +SbF_(5) to `

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Complete the following reactions : (i) XeF_(2)+H_(2)to , (ii)XeF_(6)+SiO_(2) to (iii) XeF_(6) + NH_(3) to , (iv) XeF_(6)+H_(2)O to (v) XeF_(6) + SbF_(5) to (vi) XeF_(4)+4KI to Xe + 4 KF +2I_(2) (vii) XeF_(4) + BCl_(3) overset(-78^(@)C)to

(a) Complete the following chemical equations . (i) XeF_(4) + SbF_(5) rarr , (ii) Cl_(2) + F_(2) ("excess") rarr (b) explain each of the following : (i) Nitrogen is much less reactive than phosphorus. (ii) The stability of +5 oxidation state decreases down group 15. (iii) The bond angles (O-N-O) are not of the value in NO_(2)^(-) and NO_(2)^(+) .

Complete the following equations : XeF_(4) + H_(2)O to XeF_(2) + PF_(5) to XeF_(6)+NaF to

Complete the following reactions (a) XeF_(4) + H_(2)O rarr (b) XeF_(6) + SiO_(2) rarr (c ) XeF_(6) + H_(2) rarr (d) XeF_(6) + H_(2)O rarr (e ) XeF_(6) + SbF_(5) rarr (f) XeF_(6) + NH_(3) rarr

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XeF_(6)+PF_(5) to

SbF_(3) reacts with XeF_(4) and XeF_(6) to form ionic compounds [XeF_(3)^(+)][SbF_(6)^(+)] and [XeF_(5)^(+)][SbF_(6)^(-)] then molecular shape of [XeF_(3)^(+)] ion and [XeF_(5)^(+)] ion respectively