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Solution set for inequality -8 le5x - 3 ...

Solution set for inequality `-8 le5x - 3 < 7` is (-1,2).

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To solve the inequality \(-8 \leq 5x - 3 < 7\), we will break it down step by step. ### Step 1: Split the compound inequality We can rewrite the compound inequality as two separate inequalities: 1. \(-8 \leq 5x - 3\) 2. \(5x - 3 < 7\) ### Step 2: Solve the first inequality Starting with the first inequality: \[ -8 \leq 5x - 3 \] Add 3 to both sides: \[ -8 + 3 \leq 5x \] This simplifies to: \[ -5 \leq 5x \] Now, divide both sides by 5: \[ -\frac{5}{5} \leq x \] This simplifies to: \[ -1 \leq x \quad \text{or} \quad x \geq -1 \] ### Step 3: Solve the second inequality Now, let's solve the second inequality: \[ 5x - 3 < 7 \] Add 3 to both sides: \[ 5x < 7 + 3 \] This simplifies to: \[ 5x < 10 \] Now, divide both sides by 5: \[ x < \frac{10}{5} \] This simplifies to: \[ x < 2 \] ### Step 4: Combine the results From the two inequalities we have: 1. \(x \geq -1\) 2. \(x < 2\) Combining these results gives us: \[ -1 \leq x < 2 \] ### Step 5: Write the solution set The solution set in interval notation is: \[ [-1, 2) \] ### Final Answer The solution set for the inequality \(-8 \leq 5x - 3 < 7\) is \([-1, 2)\). ---
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Knowledge Check

  • Solution set for inequality |x-1|le5 is.

    A
    [-6,4]
    B
    [-4,0]
    C
    [-4,6]
    D
    [0,6]
  • Solution set for inequality 5x-3<3x+1, xinN is-

    A
    `(-infty,2)`
    B
    {0,1,2}
    C
    {1}
    D
    `phi`
  • Consider the following ststements. I. Solution set of the inequality -15lt(3(x-2))/(5)le0 is (-23,2] II. Solution set of the inequality 7le(3x+11)/(2)le11 is [1,(11)/(3)] III. Solution set of the inequality -5le(2-3x)/(4)le9 is [-1,1]uu[3,5] Choose the correct option

    A
    Only I and II are true.
    B
    Only II and III are true.
    C
    Only I and III are true.
    D
    All are true.
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