A galvanometer of resistance `120Omega` gives full scale deflection for a current of 5mA. How can it be converted into an ammeter of range 0 to 5A? Also determine the net resistance of the ammeter.

Explanation

To convert a galvanometer into an ammeter, we need to add a shunt resistor in parallel with the galvanometer. Here's a step-by-step solution to the problem:

### Step 1: Understand the given values
- Resistance of the galvanometer (G) = 120 Ω
- Full-scale deflection current of the galvanometer (Ig) = 5 mA = 5 × 10^(-3) A
- Desired maximum current range of the ammeter (I) = 5 A

### Step 2: Calculate the current through the shunt resistor
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