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A galvanometer of resistance 120Omega gi...

A galvanometer of resistance `120Omega` gives full scale deflection for a current of 5mA. How can it be converted into an ammeter of range 0 to 5A? Also determine the net resistance of the ammeter.

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To convert a galvanometer into an ammeter, we need to add a shunt resistor in parallel with the galvanometer. Here's a step-by-step solution to the problem: ### Step 1: Understand the given values - Resistance of the galvanometer (G) = 120 Ω - Full-scale deflection current of the galvanometer (Ig) = 5 mA = 5 × 10^(-3) A - Desired maximum current range of the ammeter (I) = 5 A ### Step 2: Calculate the current through the shunt resistor ...
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Knowledge Check

  • A galvanometer has a resistance of 118Omega and gives full scale deflection for a current of 50 m A. if it is required to convert into an ammeter of range 3A, the shunt resistance should be

    A
    `0.2 Omega`
    B
    `0.28Omega`
    C
    `2Omega`
    D
    `2.8Omega`

  • A galvanometer of resistance 15 ohm gives full scale deflection for a current of 2 mA. Calculate the shunt resistance needed to convert it into an ammeter of range 0 to 5 A

    A
    `0.712ohm`
    B
    `1.203ohm`
    C
    `0.006ohm`
    D
    `0.015 ohm`

  • A galvanometer of resistance 50Omega gives full scale deflection when a current 10^(-3)A is passed through it converted into an ammeter to measure 0.5A current.

    A
    `50//499 Omega` in parallel
    B
    `9//20 Omega` in parallel
    C
    `2//99 Omega` in parallel
    D
    `20//99 Omega` in parallel

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    A galvanometer with a coil of resistance 12.0Omega shows full scale deflection for a current 2*5mA . How will you convert the meter into (i) an ammeter of range 0 to 7*5A (b) a voltmeter of range 0 to 10V.

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