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The series L–C–R circuit shown in fig. i...

The series L–C–R circuit shown in fig. is in resonance state. What is the voltage across the inductor?

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Current at resonance `I= (V)/(R )`.
`therefore` Voltage across inductor `V_(L) = I. X_(L) = I omega L = (V)/(R ) (2piv) L.`
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