0.1M NaOH is titrated with 0.1M, 20mL HA...

`0.1M NaOH` is titrated with `0.1M, 20mL HA` till the point. `K_(a)(HA) = 6 xx10^(-6)` and degree of dissociation of `HA` is neglible (small) as compared to unity. Calculate the `pH` of the resulting solution at the end point [Use `log 6 ~~ 0.8]`

6.23

9.22

7.21

8.95

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