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The solution of the differential equatio...

The solution of the differential equation `(dy)/(dx)=e^(y)(1/(2x^2)+1), (AA x gt0)` is `lambdaxe^(-y)=1-2x^(2)` (where c is an arbitrary constant). Then, the value of `lambda` is equal to

A

2

B

4

C

`(1)/(2)`

D

`(1)/(4)`

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A
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