Cell A and B are adjacent to each other . Analyse the below table and the choose the correct result.
`{:("Parameters","Cell A","Cells B"),("Osmotic pressure ",10,8),("Turgor pressure ",8,4):}`

Options

A. Water will move from Cell B to A
B. Water will show no movement .
C. Water will move from Cell A to B
D. Solute will move across both the cells.

Answer

To solve the problem regarding the movement of water between Cell A and Cell B based on the given osmotic and turgor pressures, we can follow these steps:

### Step 1: Understand the Parameters
We have two parameters provided in the table:
- **Osmotic Pressure**: This is the pressure required to prevent the flow of water across a semipermeable membrane due to osmosis.
- **Turgor Pressure**: This is the pressure exerted by the fluid (usually water) inside the cell against the cell wall.

### Step 2: Identify the Values
From the table, we have:
- For **Cell A**:
- Osmotic Pressure = 10
- Turgor Pressure = 8
- For **Cell B**:
- Osmotic Pressure = 8
- Turgor Pressure = 4

### Step 3: Calculate the Pressure Deficit (DPD)
The formula for calculating the Deficit Pressure Deficit (DPD) is:
\[ \text{DPD} = \text{Osmotic Pressure} - \text{Turgor Pressure} \]

Now, we will calculate DPD for both cells.

- **For Cell A**:
\[ \text{DPD}_A = \text{Osmotic Pressure}_A - \text{Turgor Pressure}_A = 10 - 8 = 2 \]

- **For Cell B**:
\[ \text{DPD}_B = \text{Osmotic Pressure}_B - \text{Turgor Pressure}_B = 8 - 4 = 4 \]

### Step 4: Analyze the DPD Values
Now we have:
- DPD of Cell A = 2
- DPD of Cell B = 4

Water moves from an area of lower DPD to an area of higher DPD. Therefore, since Cell A has a lower DPD (2) compared to Cell B (4), water will move from Cell A to Cell B.

### Step 5: Conclusion
The correct result is that water will move from Cell A to Cell B.

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