How many different types of gametes could be produced through the independent assortment by an individual with the genotype AaBBCcDdee?

Options

A. 8
B. 4
C. 2
D. 1

Answer

To determine how many different types of gametes can be produced through independent assortment by an individual with the genotype AaBBCcDdee, we can follow these steps:

### Step 1: Identify the Genotype
The given genotype is AaBBCcDdee.

### Step 2: Identify Heterozygous and Homozygous Alleles
- **Heterozygous Alleles**: These are alleles that are different (e.g., Aa, Cc, Dd).
- A (capital A) and a (small a) are heterozygous.
- C (capital C) and c (small c) are heterozygous.
- D (capital D) and d (small d) are heterozygous.

- **Homozygous Alleles**: These are alleles that are the same (e.g., BB, ee).
- B (capital B) and B (capital B) are homozygous.
- e (small e) and e (small e) are homozygous.

### Step 3: Count the Heterozygous Alleles
From the genotype:
- Heterozygous pairs: A/a (1), C/c (1), D/d (1)
- Total heterozygous pairs (n) = 3

### Step 4: Use the Formula for Gamete Formation
The formula to calculate the number of different types of gametes is:
\[ \text{Number of Gametes} = 2^n \]
Where \( n \) is the number of heterozygous pairs.

### Step 5: Calculate the Number of Gametes
Substituting the value of \( n \):
\[ \text{Number of Gametes} = 2^3 = 8 \]

### Conclusion
The individual with the genotype AaBBCcDdee can produce **8 different types of gametes**.

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