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A man measures the period of a simple pe...

A man measures the period of a simple pendulum inside a stationary lift and find it be T. If the lift accelerates downwards with an acceleration of `g//3`, then the period of the pendulum will be

A

`sqrt(2)T`

B

`T/(sqrt(2))`

C

`sqrt(3)/2T`

D

`T/3`

Text Solution

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The correct Answer is:
C
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