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Let a ,b ,c be real. If a x^2+b x+c=0 ha...

Let `a ,b ,c` be real. If `a x^2+b x+c=0` has two real roots `alphaa n dbeta,w h e r ealpha<<-1a n dbeta>>1` , then show that `1+c/a+|b/a|<0`

Text Solution

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The correct Answer is:
`rArr 1+(c )/(a)+|(b)/(a)|lt 0`
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