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Iceberg floats in water with part of it submerged. What is the fraction of the volume of iceberg submerged if the density of ice is `rho_i = 0.917 g cm^(-3) ?`

Text Solution

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Given , density of ice `(rho_("ice"))=0.917 g//cm^(3)`
Density of water `(rho_(w))=1 g//cm^(3)`
Let V be te total volume of the iceberg and V' of its volume be submerged in water. In floating condition.
Weight of the iceberg=Weight of the water displaced by the submerged part by ice
`Vrho_("ice")g=V'rho_(w)g`
or `(V')/(V)=(rho_("ice"))/(rho_(w))=(0.917)/(1)=0.917" "(because ` Weight =mg=`vrhog)`
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