`MnO_(4)^(2-)` undergoes disproportionation reaction in acidic medium but `MnO_(4)^(-)` does not. Given reason.

Explanation

To understand why `MnO4^(2-)` undergoes disproportionation in acidic medium while `MnO4^(-)` does not, we need to analyze the oxidation states of manganese in both species and their ability to undergo oxidation and reduction.

### Step-by-Step Solution:

**Step 1: Determine the oxidation state of manganese in `MnO4^(2-)`.**
- The formula for calculating the oxidation state is:
\[
\text{Oxidation state of Mn} + 4 \times (\text{Oxidation state of O}) = \text{Charge of the ion}
...