Balance the following ionic equation.
`MnO_(4)^(-)+H^(+)+Br^(-)toMn^(2+)+Br_(2)+H_(2)O`

Explanation

Write the O.N. of all teh atoms above their respective symbols

Divide skeleton equation into two half reactions.
Reduction half reaction `MnO_(4)^(-)toMn^(2+)`
Oxidation half reaction `Br^(-)toBr_(2)`
To balance reduction half reaction
`MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O`
To balance oxidation half reaction
`2Br^(-)toBr_(2)+2e^(-)`
To balance the reaction
`({:(2MnO_(4)^(-)+16H^(+)+10e^(-)to2Mn^(2+)+8H_(2)O),(" "10Br^(-)to5Br_(2)+10e^(-)):})/(2MnO_(4)^(-)+10Br^(-)+16H^(+)to2Mn^(2+)+5Br_(2)+8H_(2)O)`
This represent the correct balanced ionic equation