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If f(x+1)+f(x-1)=2f(x)a n df(0),=0, then...

If `f(x+1)+f(x-1)=2f(x)a n df(0),=0,` then `f(n),n in N ,` is `nf(1)` (b) `{f(1)}^n` `0` (d) none of these

A

`nf(1)`

B

`f{f(1)}^(n)`

C

0

D

none of these

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A
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