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The vertices of a triangle are `A(x_1, x_1tantheta_1),B(x_2, x_2tantheta_2)a n dC(x_3, x_3tantheta_3)dot` if the circumcentre of `"Delta"A B C` coincides with the origin and `H( x , y )` is the orthocentre, show that ` y/( x )=(sintheta_1+s intheta_2+sintheta_3)/(costheta_1+costheta_2+costheta_3)`

A

centroid of `Delta ABC`

B

incentre of `Delta ABC`

C

orthocenter of `DeltaABC`

D

ex-center of `Delta ABC`

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The correct Answer is:
A, C
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