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If sqrt(1- sin A)= sin "" A/2 - cos "" A...

If `sqrt(1- sin A)= sin "" A/2 - cos "" A/2 ` could lie in quadrant

A

first

B

second

C

third

D

fourth

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The correct Answer is:
To solve the equation \( \sqrt{1 - \sin A} = \sin \frac{A}{2} - \cos \frac{A}{2} \) and determine in which quadrants it can lie, we can follow these steps: ### Step 1: Simplify the Left Side We start with the left side of the equation: \[ \sqrt{1 - \sin A} \] Using the Pythagorean identity, we know that: \[ 1 - \sin A = \cos^2 \frac{A}{2} \] Thus, we can rewrite the left side: \[ \sqrt{1 - \sin A} = \sqrt{\cos^2 \frac{A}{2}} = |\cos \frac{A}{2}| \] ### Step 2: Analyze the Right Side Now, let's analyze the right side: \[ \sin \frac{A}{2} - \cos \frac{A}{2} \] This expression can be rewritten as: \[ \sin \frac{A}{2} - \cos \frac{A}{2} = \frac{\sqrt{2}}{2}(\sqrt{2} \sin \frac{A}{2} - \sqrt{2} \cos \frac{A}{2}) = \sqrt{2} \left(\sin \frac{A}{2} - \cos \frac{A}{2}\right) \] ### Step 3: Set Up the Equation Now we equate both sides: \[ |\cos \frac{A}{2}| = \sin \frac{A}{2} - \cos \frac{A}{2} \] ### Step 4: Solve the Inequality To solve for when this holds true, we need to consider the signs of \( \sin \frac{A}{2} \) and \( \cos \frac{A}{2} \). 1. **Case 1**: If \( \cos \frac{A}{2} \geq 0 \): \[ \cos \frac{A}{2} = \sin \frac{A}{2} - \cos \frac{A}{2} \] This simplifies to: \[ 2\cos \frac{A}{2} = \sin \frac{A}{2} \] or \[ \tan \frac{A}{2} = 2 \] 2. **Case 2**: If \( \cos \frac{A}{2} < 0 \): \[ -\cos \frac{A}{2} = \sin \frac{A}{2} - \cos \frac{A}{2} \] This simplifies to: \[ 0 = \sin \frac{A}{2} \] which gives \( \frac{A}{2} = n\pi \) where \( n \) is an integer. ### Step 5: Determine Quadrants From the equation \( \tan \frac{A}{2} = 2 \), we find the angles for \( \frac{A}{2} \): - The solutions for \( \tan \frac{A}{2} = 2 \) occur in the first and third quadrants. Thus, \( \frac{A}{2} \) can be in the first quadrant (where \( A \) is in the first quadrant) or in the third quadrant (where \( A \) is in the third quadrant). Therefore, \( A \) can lie in the following quadrants: - **2nd Quadrant**: \( \frac{A}{2} \) is in the 1st quadrant. - **3rd Quadrant**: \( \frac{A}{2} \) is in the 3rd quadrant. - **4th Quadrant**: \( \frac{A}{2} \) can also be in the 4th quadrant. ### Conclusion The values of \( A \) can lie in the 2nd, 3rd, and 4th quadrants.
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