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If in a triangle ABC, CD is the angular ...

If in a triangle `ABC, CD` is the angular bisector of the angle ACB then CD is equal to

A

`(a+b)/(2ab) cos "" C/2`

B

`(a+b)/(ab ) cos "" C/2`

C

`(2ab)/(a +b) cos ""C/2`

D

`(b sin A)/(sin (B + (C )/(2)))`

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The correct Answer is:
C, D
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