Home
Class 12
MATHS
The latus rectum of a conic section is t...

The latus rectum of a conic section is the width of the function through the focus. the possitive difference between the length of the latus rectum of `3y=x^2+4x-9"and"x^2+4y^2-6x+16 y=24` is-

Text Solution

Verified by Experts

The correct Answer is:
`0.5`
Promotional Banner

Topper's Solved these Questions

  • MATHEMATICS

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|23 Videos
  • MATHEMATICAL REASONING

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL-2|18 Videos
  • MATHEMATICS TIPS

    FIITJEE|Exercise NUMERICAL DECIMAL BASED QUESTIONS|21 Videos

Similar Questions

Explore conceptually related problems

The latus rectum of a conic section is the width of the function through the focus.the possitive difference between the length of the latus rectum of 3y=x^(2)+4x-9andx^(2)+4y^(2)-6x+16y=24 is- -

The length of the latus rectum of 3x^(2) - 2y^(2) =6 is

The length of the latus rectum of 3x^(2) -4y +6x - 3 = 0 is

The length of the latus rectum of 16x^(2) + y^(2) = 16 is

Find the length of the latus rectum of the parabola x^(2) = -8y .

The length of the latus rectum of the hyperbola 3x ^(2) -y ^(2) =4 is