A car was moving at a rate of 18 km/h. When thebrakes were applied, it comes to rest in a distance of 100 m. Calculate the reterdation produced by the brakes.

Explanation

Using the equation of motion
`v^(2)-u^(2)=2as" …(i)"`
`v=0, u=18km//h=5m//s, S=100m`
So, substituting the values in equation (i) we get
`a=(-5xx5)/(2xx100)=-(1)/(8)=-0.125m//s^(2)`
So, the retardation produced by the brakes is `0.125m//s^(2)`.