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It magnitude of average speed and averag...

It magnitude of average speed and average velocity over an interval of time are same, then

A

Particle must move with zero acceleration

B

Particle must move with uniform acceleration

C

Particle must be at rest

D

Particle must move in a straight line without turning back

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To solve the question regarding the conditions under which the magnitude of average speed and average velocity over an interval of time are the same, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Average Speed and Average Velocity**: - Average speed is defined as the total distance traveled divided by the total time taken. - Average velocity is defined as the total displacement (change in position) divided by the total time taken. 2. **Setting Up the Equation**: - Let \( T \) be the total time for the motion. - Let \( D \) be the total distance traveled. - Let \( S \) be the total displacement. - According to the question, we have: \[ \text{Average Speed} = \frac{D}{T} \] \[ \text{Average Velocity} = \frac{S}{T} \] - Given that the magnitudes of average speed and average velocity are equal, we can write: \[ \frac{D}{T} = \frac{S}{T} \] 3. **Simplifying the Equation**: - Since \( T \) is common in both terms, we can cancel it out (assuming \( T \neq 0 \)): \[ D = S \] 4. **Interpreting the Result**: - The equality \( D = S \) implies that the total distance traveled is equal to the total displacement. - This condition holds true only when the object moves in a straight line without changing direction. 5. **Conclusion**: - Therefore, the condition for the magnitudes of average speed and average velocity to be the same is that the particle must move in a straight line without turning back. ### Final Answer: The magnitude of average speed and average velocity over an interval of time are the same when the particle moves in a straight line without changing direction. ---
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