A : The magntidue of average velocity in an interval can never be greater than average speed in that interval.
R : For a moving object distance traveled `ge"|Displacement|"`

Options

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1).
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2).
C. If Assertion is true statement but Reason is false, then mark (3).
D. If both Assertion and Reason are false statement, then mark (4).

Answer

To solve the given question, we need to analyze the assertion (A) and the reason (R) provided.

**Assertion (A):** The magnitude of average velocity in an interval can never be greater than average speed in that interval.

**Reason (R):** For a moving object, distance traveled is greater than or equal to the magnitude of displacement.

### Step-by-Step Solution:

1. **Understanding Average Velocity and Average Speed:**
- Average velocity is defined as the total displacement divided by the total time taken. Mathematically, it is expressed as:
\[ \text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} \]
- Average speed is defined as the total distance traveled divided by the total time taken. It can be expressed as:
\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]

2. **Comparison of Average Velocity and Average Speed:**
- Since average velocity is based on displacement and average speed is based on distance, we need to consider the relationship between distance and displacement.
- For any moving object, the distance traveled is always greater than or equal to the magnitude of displacement. This is expressed as:
\[ \text{Distance} \geq |\text{Displacement}| \]

3. **Analyzing the Assertion:**
- Given the definitions, if we consider the relationship between average velocity and average speed:
\[ \text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} \quad \text{and} \quad \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]
- Since the total distance is always greater than or equal to the total displacement, it follows that:
\[ \text{Average Speed} \geq \text{Average Velocity} \]
- Therefore, the assertion that the magnitude of average velocity can never be greater than average speed is correct.

4. **Analyzing the Reason:**
- The reason states that for a moving object, the distance traveled is greater than or equal to the magnitude of displacement, which is a fundamental property of motion.
- This statement is also correct.

5. **Conclusion:**
- Both the assertion (A) and the reason (R) are correct. The assertion correctly states that the magnitude of average velocity can never exceed average speed, and the reason accurately describes the relationship between distance and displacement.

### Final Answer:
Both the assertion and reason are correct.