25 ml of `(N)/(10)` caustic soda solution exactly neuralised 20ml of an acid solution contaning `7.875gm` of acid per litre. What will be the equivalent mass of acid?
Text Solution
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`underset((NaOH))(N_(1)V_(1))=underset(("Acid"))(N_(2)V_(2))` `(1)/(10)xx25=N_(2)xx20` `N_(2)=(25)/(10xx20)=0.125` Strength =Normality `xx` Eq. mass Eq. mass of the acid`=(7.875)/(0.125)=63.00`
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