`0.56 g` of lime stone was treated with oxalic acid to give `CaC_(2)O_(4)`. The precipitate decolorized `45 ml` of `0.2N KMnO_(4)` in acid medium. Calculate `%` of `CaO` in lime stone.
Text Solution
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`45 mL " of" 0.2 N KMnO_(4)=45 mL " of" 0.2 N CaC_(2)O_(4)` `=45 mL " of " 0.2 N CaCO_(3)` `=45 mL " of" 0.2 N CaO` Mass of CaO`=(N xx E xx V)/(1000)=(0.2xx28xx45)/(1000)=0.252 g` % of CaO in limestone`=(0.252)/(0.56)xx100=45`
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