The saponification number of fat or oil ...

The saponification number of fat or oil is defined as the number of mg of KOH required to saponify 1 g oil or fat. A sample of peanut oil weighing 1.5763 g is added to 25 mL of 0.421 M KOH. After saponification is complete, 8.46 mL of `0.2732 M K_(2)SO_(4)` is needed to neutralise excess of KOH. What is the saponification number of peanut oil ?

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The correct Answer is:

209.8

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A sample of peanut oil weighing 1.5763 g is added to 25 mL "of" 0.4210 M KOH . After saponification is complete 8.46 mL "of" 0.2732 M H_(2)SO_(4) is needed to neutralize excess KOH . The saponification number of peanut oil is:

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