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3.45 g of a metallic carbonate were mixe...

3.45 g of a metallic carbonate were mixed with 240 mL of `N//4` HCl. The excess acid was neutralised by 50 mL of `N//5` KOH solution. Calculate the equivalent mass of the metal.

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Equivalent mass of metal carbonate
`=(3.45xx4xx1000)/(200)=69`
Equivalent mass of metal =69- Eq. mass of carbonate
=(69-30)=39
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