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1.2 g of a sample of CaOCl(2) were suspe...

1.2 g of a sample of `CaOCl_(2)` were suspended in water made up to 100 mL. 25 mL of this solution was treated with KI and the `I_(2)` liberated corresponded to 10 mL of `N//25` hypo. Calculate the percentage of `Cl_(2)` available in `CaOCl_(2)`.

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The correct Answer is:
`4.7%`
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