The formula weight of an acid is 82. In a titration, `100 cm^(3)` of a solution of this acid containing 39.0 g of the acid per litre were completely neutralised by `95.0 cm^(3)` of aqueous NaOH containing 40.0 g of NaOH per litre. What is the basicity of the acid ?

Explanation

Normality of NaOH=1
Normality of acid `=(1xx95)/(100)=0.95`
Let the eq. mass of the acid be E.
`therefore (39)/(E )=0.95 " or " E=41, " " "Basicity"=(82)/(41)=2`