Calculate the quantity of sodium carbonate (anhydrous) required to prepare 250mL `(M)/(10)` solution.

Explanation

We know that,
Molarity `= (w)/(M xx V)`
where, w = mass of `Na_(2)CO_(3)` in g,
M = molecular mass of `Na_(2)CO_(3)` in gram = 106
V = volume of solution in litre `= (250)/(1000)=0.25`
Molarity `= (1)/(10)`
Hence, `(1)/(10)=(w)/(106xx0.25)`
or `w=(106xx0.25)/(10)=2.65g`.