Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

Explanation

Strength of the solution
= Molarity `xx` mol. Mass
`=2.03 xx60 = 121.8 g//L`
Density of solution `= 1.017 g//mL`
Mass of 1 litre of solution `= 1000 mL xx 1.017 g//mL`
`=1017 g`
Mass of water `= 1017 - 121.8 = 895.2g = (895.2)/(1000)kg`
Molality `= (2.03)/(895.2)xx1000=2.267m`.