How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?

Explanation

Number of moles of `NaCl = (MV)/(1000)`
`= (0.5 xx 50)/(1000)=0.025`
`NaCl rarr Na^(+) +Cl^(-)`
Number of moles of `Na^(+)=` Number of moles of NaCl
`= 0.025`
Number of ions of `Na^(+)=0.025 xx 6.023 xx 10^(23)`
`= 1.505 xx 10^(22)`.