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By dissolving 13.6 g of a substance in 2...

By dissolving `13.6 g` of a substance in `20 g` of water, the freezing point decreased by `3.7^(@)C`. Calculate the molecular mass of the substance. (Molal depression constant for water `= 1.863K kg mol^(-1))`

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`m=(1000K_(f)xxw)/(WxxDeltaT)`
Given, `K_(f)=1.863"K kg mol"^(-1)`
`w = 13.6g,W=20g,Delta T=3.7^(@)C`
`m=(1000xx1.863xx13.6)/(20xx3.7)=342.39`.
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OP TANDON-SOLUTIONS (GENERAL AND COLLIGATIVE PROPERTIES)-Self Assessment
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