A solution is prepared by dissolving `1.08 g` of human serum albumin, a protein obtained from blood plasma, in `50 cm^(3)` of aqueous solution. The solution has an osmotic pressure of `5.85 mm Hg` at `298 K`.
a. What is the molar mass of albumin ?
b. What is the height of water column placed in solution ?
`d_((H_(2)O)) =1 g cm^(-3)`

Explanation

(a) Molar mass of albumin can be calculated using following relation :
`m_(B)=(w_(B)xxRT)/(piV)`....(i)
Given, `w_(B)=1.08g,R=0.0821 " litre atm K"^(-1)"mol"^(-1)`
Substituting these values in eq. (i)
`m_(B)=(1.08xx0.0821xx298)/((5.85//760)xx0.05)=68655g//mol`
(b) `pi=h.d.g`
`(5.85)/(760)xx101325=hxx1xx10^(-3)xx9.8`
`:. h=7.958xx10^(4)` m
`=7.968xx10^(6)` cm.