Calculate osmotic pressure of a solution obtained by mixing `100 mL` of `3.4%` solution "(weight/volume)" of urea "(molecular weight 60)" and `100 mL` of `1.6%` solution "(weight/volume)" of cane sugar "(molecular weight 342)" at `20^(@)C`.

Explanation

No. of moles of urea `= (3.4)/(60)=0.0567`
No. of moles of can sugar `=(1.6)/(342)=0.0047`
Total number of moles `=(0.0567+0.0047)=0.0614`
Total volume of solution `= (100+100)=200` mL
`=0.1` litre
PV = (Total number of moles) `xx S xx T`
`P=(0.0614)/(0.2)xx0.0821xx293=7.385`atm.