Calculate the boiling point of a solution containing `0.61 g` of benzoic acid in `50 g` of carbon disulphide assuming `84%` dimerization of the acid. The boiling point and `K_(b)` of `CS_(2)` are `46.2^(@)C` and `2.3 kg mol^(-1)`.

Explanation

`Delta T = i xx K_(b) xx` Molality
`= ixxK_(b)xx(wxx1000)/(mxxW)`
`alpha=(1-i)/(1-1//n)`
`0.84=(1-i)/(1-1//2)`
`i=0.58`
`DeltaT=0.58xx2.3xx(0.61xx1000)/(122xx50)=0.1334`
`T-T_(0)=0.1334`
`T=T_(0)+0.1334-46.2+0.1334=46.3334`.