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How many Na^(+) ions are present in 50mL...

How many `Na^(+)` ions are present in 50mL of a 0.5 M solution of `NaCl` ?

A

0.125 mol , 7.32 g

B

7.32 mol , 0.125 g

C

0.125 mol, 0.125 g

D

7.32 mol , 7.32 g

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles `= (MV)/(1000)=(0.5xx250)/(1000)=0.125`
Mass of NaCl `=58.5xx0.125=7.32g`]
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