Density of 2.05 M solution of acetic aci...

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

A

`"1.14 mol kg"^(-1)`

B

`"3.28 mol kg"^(-1)`

C

`"2.28 mol kg"^(-1)`

D

`"0.44 mol kg"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

C

`m=(Mxx1000)/(1000d-Mm_(B))=(2.05xx1000)/(1000xx1.02-2.05xx60)`
`=2.28"mol kg"^(-1)`]

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