The vapour pressure of pure benzene at `88^(@)C` is `957 mm` and that of toluene at the same temperature is `379.5 mm`. The composition of benzene-toluene mixture boiling at `88^(@)C` will be

Options

A. `x_("benzene")=0.66,x_("toluene")=0.34`
B. `x_("benzene")=0.34,x_("toluene")=0.66`
C. `x_("benzene")=x_("tolulene")=0.5`
D. `x_("benzene")=0.75,x_("toluene")=0.25`

Answer

A

Explanation

`p=p_("benzene")^(0)x_("benzene")+p_("tolulene")^(0)x_("toluene")`
`760=957.x_("benzene")+379.5(1-x_("benzene"))`
`x_("benzene")=0.66`
and`x_("toluene")=1-0.66=0.34`]