The vapour pressure of water at 23^(@)C ...

The vapour pressure of water at `23^(@)C` is 19.8 mm. 0.1 mole glucose is dissolved in 178.2g of water. What is the vapour pressure (in mm) of the resultant solution ?

19.602

19.402

19.202

Text Solution

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The correct Answer is:

`n_(B)=0.1,n_(A)=(178.2)/(18)=9.9`
`x_(A)=(n_(A))/(n_(A)+n_(B))=(9.9)/(9.9+0.1)=0.99`
`p=p_(0)x_(A)`
`=19.8xx0.99=19.602` mm]

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