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A 0.2 molal solution of KCl freezes at -...

A `0.2 molal` solution of `KCl` freezes at `-0.68^(@)C`. If `K_(f)` for `H_(2)O` is `1.86`, the degree of dissociation of `KCl` is
a.`85%` , b.`83%` , c. `65%` , d. `90%`

A

0.75

B

0.83

C

0.65

D

0.92

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT=ixxK_(f)xxm`
`0.68=ixx1.86xx0.2`
`i=1.83`
`alpha=(i-1)/(n-1)`
`=(1.83-1)/(2-1)=0.83`
Ionization = 83%].
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