Calculate the molarity of each ion in solution after 2.0 litre of 3.0 M `AgNO_(3)` is mixed with 3.0 litre of 1.0 M `BaCl_(2)`.

Answer

Molarity of `Ba^(2+)=0.6 M` ; Molarity of `NO_(3)^(-)=1.2 M`]

Explanation

`{:(,BaCl_(2),+,2AgNO_(3),=,2AgCl darr,+,Ba(NO_(3))_(2)),("Initial","3 mole",,"6 mole",,"6 mole Ag"^(+),,Ba(NO_(3))_(2)),(,Ba^(2+),,Ag^(+)"",,"with 6 mole Cl"^(-),,"to form"),(,"6 mole Cl"^(-),,"6 mole",,"AgCl(s)",,),(,,,NO_(3)^(-)",",,,,):}`
`{:("After","3 mole","6 mole"),("reaction",Ba^(2+),NO_(3)^(-)):}`
The volume `3.0 + 2.0 = 5` litre]