Calculate the amount of ice that will separate out on cooling a solution containing `50` g of ethylene glycol in `200` g water to `-9.3^(@)C` `(K_(f)` for water `= 1.86 "K kg mol"^(-1))`

Explanation

`DeltaT=K_(f)xxm`
`9.3=1.86xxm`
or `m=5`
Thus, solution of `5.0` molality will have freezing point of `-9.3^(@)C`.
Let `W` g water be needed to prepare `5.0` molal solution containing `(50)/(62)` mole of ethylene glycol
So, `(50xx1000)/(62xxW)=5.0`
or `W=(50xx1000)/(62xx5)=161.3g`
Hence, ice separating out `= 200 - 161.3 = 38.7g`