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0.1 formal soluton of NaCl is found to b...

0.1 formal soluton of NaCl is found to be isotonic with 1.10% solution of urea. Calculate the apparent degree of ionization of NaCl.

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Verified by Experts

The correct Answer is:
0.83
`pi_(NaCl)=pi_(urea)`
`=nxx(1)/(V)RT`
`ixx0.1xxRT=(1.1)/(60xx0.1)xxRT" "(pi=(n)/(V)RT)`
`i=83`
`alpha=(i-1)/(n-1)=(1.83-1)/(2-1)=0.83`]
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