Home
Class 11
CHEMISTRY
An aqueous solution of glucose was prepa...

An aqueous solution of glucose was prepared by dissolving 18g of glucose in 90g of water. The relative lowering in vapour pressure is

A

6

B

0.2

C

5.1

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
D

`(Deltap)/(p_(0))=x_(B)=(n_(B))/(n_(A)+n_(B))=((18)/(180))/((90)/(18)+(18)/(180))`
`=(0.1)/(5.1)=0.02`]
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS (GENERAL AND COLLIGATIVE PROPERTIES)

    OP TANDON|Exercise Set-2 (Level-A)|22 Videos
  • SOLUTIONS (GENERAL AND COLLIGATIVE PROPERTIES)

    OP TANDON|Exercise Level-B|53 Videos
  • SOLUTIONS (GENERAL AND COLLIGATIVE PROPERTIES)

    OP TANDON|Exercise Practice Problem|66 Videos
  • PROBLEMS BASED UPON STRUCTURES AND REACTIONS OF ORGANIC COMPOUNDS

    OP TANDON|Exercise Some Solved Problems|21 Videos
  • STATES OF MATTER (GASES AND LIQUIDS)

    OP TANDON|Exercise Self Assess,ent|28 Videos

Similar Questions

Explore conceptually related problems

3g urea is dissolved in 45g of water. The relative lowering of vapour pressure is :

6g of urea is dissolved in 90g of water. The relative lowering of vapour pressure is equal to

(a) A solution is prepared by dissolving 10g of non-volatile solute in 180g of H_(2)O . If the relative lowering of vapour pressure is 0.005 , find the molar mass of the solute. (b) How many grams of sucrose (C_(12)H_(22)O_(11)) must be dissolved in 90g of water to produce a solution over which the relative humidity is 80% ? Assume the solution is ideal.

S34.2 g of cane sugar is dissolved in 180 g of water. The relative lowering of vapour pressure will be

An aqueous solution of glucose is made by dissolving 10 g of glucose in 90 g water at 303 K. If the V.P. of pure water at 303 K be 32.8 mm Hg, what would be V.P. fo the solution ?

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea =60 g "mol"^(-1) )

OP TANDON-SOLUTIONS (GENERAL AND COLLIGATIVE PROPERTIES)-Set-1 (Level-A)
  1. A molal solution is one that contains one mole of a solute in

    Text Solution

    |

  2. In which mode of expression, the concentration of a solution remains i...

    Text Solution

    |

  3. An aqueous solution of glucose was prepared by dissolving 18g of gluco...

    Text Solution

    |

  4. If 18 g of glucose is present in 1000 g of solvent, the solution is sa...

    Text Solution

    |

  5. The molarity of pure water is

    Text Solution

    |

  6. Mole fraction of the solute in a 1 molal aqueous solution is :

    Text Solution

    |

  7. Mole fraction of C(3)H(5)(OH)(3) in a solution of 36g of water and 46g...

    Text Solution

    |

  8. H(2)O(3) solution used for hair bleachingm is sold as a solution appr...

    Text Solution

    |

  9. The number of moles of solute per kg of a solvent is called its :

    Text Solution

    |

  10. 1000 gram aqueous solution of CaCO(3) contains 10 gram of carbonate. C...

    Text Solution

    |

  11. A solution of CaCl(2) is 0.5 mol/litre , then the moles of chloride io...

    Text Solution

    |

  12. What is the normality of 1 M H(3)PO(4) solution ?

    Text Solution

    |

  13. The molarity of a 0.2 N Na(2)CO(3) solution will be :

    Text Solution

    |

  14. Colligative properties of the solution depend upon :

    Text Solution

    |

  15. Which of the following is a colligative property ?

    Text Solution

    |

  16. Which os not a colligative property ?

    Text Solution

    |

  17. Colligative properties are applicable to :

    Text Solution

    |

  18. On mixing, heptane and octane form an ideal solution. At 373K the vapo...

    Text Solution

    |

  19. The vapour pressure of water at room temperature is 30 mm of Hg. If th...

    Text Solution

    |

  20. A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of...

    Text Solution

    |